Codeforces-SolutionsA/Codes/1968 C - Assembly via Remainders/1968C.cpp

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#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define endl '\n'
#define sz(x) (int)(x).size()
#define FAST (ios_base::sync_with_stdio(false), cin.tie(nullptr));
ll pow(ll x,ll y,ll m=1e9+7){ll ans=1;x%=m;while(y){if(y&1)ans=(ans*x)%m;x=(x*x)%m;y>>=1;}return ans;}
void solve()
{
ll n;
cin>>n;
vector<ll>v(n-1),ans;
for(auto &i:v) cin>>i;
ans.push_back(v.back());
ans.push_back(1e9);
for(ll i=n-3; i>=0; --i) ans.push_back(ans.back()-v[i]);
reverse(ans.begin(),ans.end());
for(auto x:ans) cout<<x<<" ";
cout<<endl;
}
signed main()
{
FAST;
int TCS = 1;
cin >> TCS;
for (int TC = 1; TC <= TCS; ++TC)
{
// cout<<"Case "<<TC<<": ";
solve();
}
}