Codeforces-SolutionsA/Codes/1968 G1 - Division + LCP (easy version)/1968G1.cpp

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#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define endl '\n'
#define FAST (ios_base::sync_with_stdio(false), cin.tie(nullptr));
ll pow(ll x,ll y,ll m=1e9+7){ll ans=1;x%=m;while(y){if(y&1)ans=(ans*x)%m;x=(x*x)%m;y>>=1;}return ans;}
vector<int>Zfunc(string &str)
{
int n=str.size();
vector<int>z(n);
int l=0,r=0;
for(int i=1;i<n;i++)
{
if(i<=r) z[i]=min(r-i+1,z[i-l]);
while(i+z[i]<n&&str[z[i]]==str[i+z[i]]) z[i]++;
if(i+z[i]-1>r)
{
l=i;
r=i+z[i]-1;
}
}
return z;
}
void solve()
{
int n, k;
string s;
cin>> n >> k >> k >> s;
vector<int>z = Zfunc(s);
ll low = 1, high = n, ans = 0;
while(low <= high)
{
ll mid = low + (high - low) / 2;
ll cnt = 1;
for(int i = mid;i < n;)
{
if(z[i] >= mid)
{
cnt++;
i += mid;
}
else i++;
}
if(cnt >= k)
{
ans = mid;
low = mid+1;
}
else high = mid-1;
}
cout<<ans<<endl;
}
signed main()
{
FAST;
int TCS = 1;
cin >> TCS;
for (int TC = 1; TC <= TCS; ++TC)
{
// cout<<"Case "<<TC<<": ";
solve();
}
}